A) \[\lambda =\frac{{{\lambda }_{1}}+{{\lambda }_{2}}}{2}\]
B) \[\frac{1}{{{\lambda }^{2}}}=\frac{1}{\lambda _{1}^{2}}+\frac{1}{\lambda _{2}^{2}}\]
C) \[\frac{2}{\lambda }=\frac{1}{{{\lambda }_{1}}}+\frac{1}{{{\lambda }_{2}}}\]
D) \[\lambda =\sqrt{{{\lambda }_{1}}{{\lambda }_{2}}}\]
Correct Answer: B
Solution :
\[P_{1}^{2}+P_{2}^{2}={{P}^{2}}\] \[\Rightarrow \] \[\frac{1}{{{\lambda }^{2}}}=\frac{1}{\lambda _{1}^{2}}+\frac{1}{\lambda _{2}^{2}}.\]You need to login to perform this action.
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