A) \[{{10}^{4}}\]
B) \[{{10}^{3}}\]
C) \[{{10}^{2}}\]
D) \[{{10}^{6}}\]
Correct Answer: A
Solution :
\[{{R}_{e}}=\frac{dv\rho }{\eta }\] \[=\frac{({{10}^{-1}})\left( \frac{{{10}^{-1}}}{60} \right)\left( \frac{1}{\pi 25\times {{10}^{-4}}} \right)({{10}^{3}})}{{{10}^{-3}}}\] \[\simeq 212.\times {{10}^{3}}\] Order \[={{10}^{4.}}\]You need to login to perform this action.
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