A) \[\frac{B\pi {{r}^{2}}I}{N}\]
B) Zero
C) \[B\pi {{r}^{2}}IN\]
D) \[\frac{B{{r}^{2}}I}{\pi N}\]
Correct Answer: C
Solution :
\[\tau =NI\pi {{r}^{2}}B\sin 90{}^\circ =B\pi {{r}^{2}}IN.\]You need to login to perform this action.
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