A) \[2+log\text{ }2\]
B) \[10-log\,2\]
C) 7
D) 6
Correct Answer: D
Solution :
Kw at \[90{}^\circ C\] is \[{{10}^{-12}}\] Hence, Neutral point is 6 So, on adding \[pH=2({{10}^{-2}}{{H}^{+}})\] and \[pH=10({{10}^{-2}}OH)\] Solution lead to the formation of neutral solution i.e. \[pH=6\]You need to login to perform this action.
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