A)
B)
C)
D)
Correct Answer: C , D
Solution :
[a] \[\text{C}{{\text{H}}_{3}}-\text{C}{{\text{H}}_{2}}-\text{C}{{\text{H}}_{2}}-\overset{\overset{O}{\mathop{\parallel }}\,}{\mathop{\text{C}}}\,-\text{ON}{{\text{a}}^{+}}\xrightarrow{\text{Electrolysis}}\,n-\text{hexane}\] [b] \[\text{C}{{\text{H}}_{3}}-{{\overset{\overset{\text{Br}}{\mathop{\text{ }\!\!|\!\!\text{ }}}\,}{\mathop{\text{CH}}}\,}_{2}}{{\overset{\overset{\text{Br}}{\mathop{\text{ }\!\!|\!\!\text{ }}}\,}{\mathop{\text{CH}}}\,}_{2}}\xrightarrow[-ZnBr]{Zn}\text{C}{{\text{H}}_{3}}-\text{C}{{\text{H}}_{2}}=\text{C}{{\text{H}}_{2}}\] [c] \[\text{C}{{\text{H}}_{3}}-\text{C}{{\text{H}}_{2}}-\text{C}{{\text{H}}_{2}}-\text{Cl}\xrightarrow{\text{Zn}+\text{HCl}}\text{C}{{\text{H}}_{3}}-\text{C}{{\text{H}}_{2}}-\text{C}{{\text{H}}_{2}}\] [d] \[\text{C}{{\text{H}}_{3}}-\text{C}{{\text{H}}_{2}}-\text{C}{{\text{H}}_{2}}-\text{CO}{{\text{O}}^{-\,}}\text{N}{{\text{a}}^{+}}\xrightarrow{\text{NaOH}+\text{CaO}}\text{CH}-\text{C}{{\text{H}}_{2}}-\text{C}{{\text{H}}_{3}}\]Solution :
Same as above
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