A) 0.853
B) 8.53
C) 0.75
D) 7.5
Correct Answer: C
Solution :
At path difference \[\frac{\lambda }{6},\]phase difference is \[\frac{\pi }{3}\] \[I={{I}_{0}}+{{I}_{0}}+2{{I}_{0}}\cos \frac{\pi }{3}=3\,{{I}_{0}}\] \[{{I}_{\max }}=4{{I}_{0}}\] So the required ratio is \[\frac{3{{I}_{0}}}{4{{I}_{0}}}=0.75\]You need to login to perform this action.
You will be redirected in
3 sec