A) 60
B) 55
C) 50
D) 40
Correct Answer: D
Solution :
In \[\Delta ABC\] |
\[\frac{10}{\sin 60{}^\circ }=\frac{b}{\sin 50{}^\circ }=\frac{c}{\sin 70{}^\circ }=K\] |
\[\frac{20}{\sqrt{3}}=\frac{b}{\sin 50{}^\circ }=\frac{c}{\sin 70{}^\circ }=K\] |
\[b=\frac{20}{\sqrt{3}}\sin 50{}^\circ \] |
\[c=\frac{20}{\sqrt{3}}\sin 70{}^\circ \] |