A) 2
B) 1
C) 1
D) 1
Correct Answer: A
Solution :
Using power of C \[BC\cdot AC=C{{S}^{2}}\] \[\therefore \] \[BC\cdot AC={{\left( \frac{1+2-1}{\sqrt{2}} \right)}^{2}}=2\]You need to login to perform this action.
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