A) an increasing function
B) a decreasing function
C) a constant function
D) None of these
Correct Answer: A
Solution :
We have, \[g''(x)-3g'(x)>3\] |
\[\Rightarrow \]\[\frac{g''(x)}{g'(x)+1}>3\] |
On integrating, we get \[\log \,(g'(x)+1)>3x\] |
\[\Rightarrow \]\[g'(x)+1>{{e}^{3x}}\] |
\[g'(x)+1>0\forall x>0\] |
\[\therefore \]\[g(x)+x\]is an increasing function. |
You need to login to perform this action.
You will be redirected in
3 sec