In the circuit shown the cells are ideal & of equal e.m.f., the capacitance of the capacitor is C and the resistance of the resistor is R. X is first joined to Y and then to Z. After a long time the total heat produced in the resistor will be - |
A) Equal to the energy finally stored in the capacitor
B) Half of the energy finally stored in take capacitor
C) Twice the energy finally stored in the capacitor
D) 4 times the energy finally stored in the capacitor
Correct Answer: D
Solution :
\[Energ{{y}_{\operatorname{Released}}}\] in xy joint |
\[=(C.V).V-\frac{1}{2}C{{V}^{2}}=\frac{1}{2}C{{V}^{2}}\] |
\[Energ{{y}_{\operatorname{Released}}}\]in xz joint |
\[=(2C.V).V-\frac{1}{2}C{{V}^{2}}=\frac{3}{2}C{{V}^{2}}\] |
Total \[hea{{t}_{\operatorname{Released}}}=2C{{V}^{2}}\] which is 4 times energy store. |
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