A) \[\frac{x+3}{3}=\frac{y-5}{1}=\frac{z-2}{-\,5}\]
B) \[\frac{x+3}{-\,3}=\frac{y-5}{-\,1}=\frac{z+2}{5}\]
C) \[\frac{x-3}{3}=\frac{y+5}{1}=\frac{z-2}{-\,5}\]
D) \[\frac{x-3}{-\,3}=\frac{y+5}{-\,1}=\frac{z-2}{5}\]
Correct Answer: A
Solution :
Line is parallel to plane Image of (1, 3, 4) is \[(-\,3,5,2).\]You need to login to perform this action.
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