A) \[(-1,0)\cup \,(0,1)\]
B) (1, 2)
C) \[(-2,-\,1)\]
D) \[(-\infty ,-\,2)\cup \,(2,\infty )\]
Correct Answer: A
Solution :
\[{{a}^{2}}=3{{t}^{2}}-2t\] For non-integral solution \[0<{{a}^{2}}<1\] \[a\in (-1,0)\cup (0,1).\]You need to login to perform this action.
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