A) 5.6 amp
B) 7.2 amp
C) 8.85 amp
D) 11.2 amp
Correct Answer: C
Solution :
Let x gm of Zn deposit on 9 gm of Hg |
% of Zn in Amalgam\[=\frac{{{m}_{Zn}}\times 100}{{{m}_{Zn}}+{{m}_{Hg}}}=\frac{x}{9+x}\times 100=25\] |
\[\therefore \] \[x=3\,gm\] |
Eq. of \[Zn=\frac{3\times 2}{65.4}\] |
\[\frac{{{n}_{Zn}}}{1}=\frac{{{n}_{{{e}^{-}}}}}{2}=\frac{Q}{2f}=\frac{it}{2f}\] |
Current \[i=\frac{6}{65.4}\times \frac{96500}{1000}=8.85\,amp.\] |
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