A) I + B
B) I
C) \[B{{\,}^{-\,\,1}}\]
D) \[({{B}^{\,-\,\,1}})'\]
Correct Answer: B
Solution :
\[B={{A}^{-\,1}}A'\]\[\Rightarrow \] AB = A' \[ABB'=A'B'=(BA)'\] \[=({{A}^{-1}}A'A)=({{A}^{-1}}AA')'=A\] \[\Rightarrow \] \[BB'=I.\]You need to login to perform this action.
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