A) \[\frac{\sqrt{3}}{\sqrt{2}}\]
B) \[\frac{\sqrt{3}}{2}\]
C) \[\frac{1}{2}\]
D) \[\frac{1}{4}\]
Correct Answer: D
Solution :
According to the figure, |
\[{{(1+y)}^{2}}={{(1-y)}^{2}}+1\,(y>0)\] |
\[\Rightarrow \] \[y=\frac{1}{4}.\] |
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