An unstable radioactive substance decays into a daughter product, but this in turn will probably itself decay until, a stable non-decaying isotope is formed. The list of all members is called a radioactive series. An example of a series is |
\[_{90}^{232}Th\xrightarrow{\alpha }_{88}^{228}Ra\xrightarrow{\beta }_{89}^{228}AC\xrightarrow{\beta }\] |
\[_{90}^{232}Th\xrightarrow{\alpha }_{88}^{228}Ra\xrightarrow{a}_{89}^{228}Ra\xrightarrow{\alpha }_{84}^{216}Po\] |
Now, choose the correct option. |
A) \[{}^{232}Th\]and \[{}^{228}Th\]are isobars
B) \[{}^{228}Ra\] and \[{}^{228}Ac\]are isotopes
C) \[{}^{232}Th\] and \[{}^{220}Ra\]are isotones
D) After some time all the members of series are in equilibrium
Correct Answer: D
Solution :
As, \[{{\lambda }_{1}}{{N}_{1}}={{\lambda }_{2}}{{N}_{2}}={{\lambda }_{3}}{{N}_{3}}.......\]etc., production rates of daughter nuclei are equal to decay rate of parent.You need to login to perform this action.
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