A) \[2\,\,\Omega \,m\]
B) \[0.4\,\,\Omega m\]
C) \[4\,\,\Omega m\]
D) \[0.2\,\,\Omega m\]
Correct Answer: B
Solution :
\[j\,=\,\sigma \text{E}\,=\,\text{ne}{{\text{v}}_{d}}\] \[\sigma \,=\,ne\,\frac{{{v}_{d}}}{\text{E}}\,=\,ne\mu \] \[\frac{1}{\sigma }\,=\rho \,=\,\frac{1}{{{n}_{e}}e{{\mu }_{e}}\,}=\,\frac{1}{{{10}^{19}}\times 1.6\times {{10}^{-19}}\times 1.6}\,=\,0.39\] = 0.4 Ωm.You need to login to perform this action.
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