A) 0.05
B) 0.1
C) 0.16
D) 0.21
Correct Answer: C
Solution :
Given, weight of \[CuC{{l}_{2}}=13.44g\] |
Molecular weight of \[CuC{{l}_{2}}=13.44g\] |
\[\text{Molality}=\frac{\text{Number}\,\text{of}\,\text{moles}\,\text{of}\,\text{solute}}{\text{Mass}\,\text{of}\,\text{solvent}\,\text{(kg)}}\] |
\[\because \]No. of moles of solute, \[CuC{{l}_{2}}=\frac{13.44}{134.1}\]? |
\[\therefore \] Molality \[=\frac{\frac{13.44}{134.1}}{1}=0.1\] |
Now, \[CuC{{l}_{2}}\underbrace{C{{u}^{2+}}+2C{{l}^{-}}}_{3particles}\] |
\[\therefore \]\[i=3\] |
\[\Rightarrow \]\[\Delta {{T}_{b}}=i{{K}_{b}}\cdot m=3\times 0.52\times 0.1\] |
\[=0.156\approx 0.16\] |
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