s
A) One - one but not onto
B) One - one and onto
C) Onto but not one - one
D) Neither one - one nor onto
Correct Answer: C
Solution :
| \[\because f(x)={{\log }_{0.5}}({{x}^{2}}-5x+6)\] |
| \[\Rightarrow f(x)\] will be defined if \[{{x}^{2}}-5x+6>0\] |
| \[\Rightarrow (x-2)\,\,(x-3)>0\] |
|
| from graph of f(x) we can say that it will be a many -one and onto function. |
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