Power dissipated in given circuit is |
A) 12 W
B) 24 W
C) 36 W
D) 72 W
Correct Answer: A
Solution :
Let current distribution is | |
By loop rule in loops 1 and 2, we have | |
\[5x-2y+3z=0\] | ?(i) |
\[2x-4y-9z=0\] | ?(ii) |
\[\Rightarrow \]\[\frac{x}{30}=\frac{y}{51}=\frac{z}{-16}=k\](let) |
\[\Rightarrow \]\[x=30k,\]\[y=51k,\]\[z=-16k\] |
If R = equivalent resistance of circuit, then\[V=R\,(x+y)\] |
\[\Rightarrow \]\[7x-2z=R\,(x+y)\] |
\[\Rightarrow \]\[R=\frac{7x-2z}{x+y}=\frac{7\times 30k-2\,(-16k)}{30k+51k}\]\[\Rightarrow \]\[R=\frac{242}{81}=3\Omega \] |
So, power dissipated, \[P=\frac{{{V}^{2}}}{R}=\frac{36}{3}=12W\] |
You need to login to perform this action.
You will be redirected in
3 sec