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KVPY Sample Paper KVPY Stream-SX Model Paper-16

  • question_answer
    Partial pressures of components of a gaseous mixture are as given below.
    Hydrogen : 200 mm Hg
    Carbon-dioxide : 150 mm Hg
    Methane : 320 mm Hg
    Ethylene : 105 mm Hg
    Percentage of mass of hydrogen in mixture is around

    A) 2.5%

    B) 0.025%

    C) 2.3%

    D) 0.23%

    Correct Answer: A

    Solution :

    From gas laws. we have \[m=M\cdot \left( \frac{pV}{RT} \right)\]
    Mass of hydrogen gas present is \[{{m}_{H}}={{M}_{H\,}}{{p}_{H}}\left( \frac{V}{RT} \right)\]
    Percentage of mass of hydrogen is
    \[{{m}_{H}}=\frac{{{M}_{H}}{{p}_{H}}\left( \frac{V}{RT} \right)\times 100}{({{M}_{H}}{{p}_{H}}+{{M}_{C{{O}_{2}}}}{{p}_{C{{O}_{2}}}}+{{M}_{C{{H}_{4}}}}{{p}_{C{{H}_{4}}}})}\]\[+{{M}_{{{C}_{2}}{{H}_{6}}}}{{p}_{{{C}_{2}}{{H}_{6}}}})\left( \frac{V}{RT} \right)\]
    \[=\frac{2\times 200\times 100}{2\times 200+44+150+16\times 320+30\times 105}\]
    \[=0.026\times 100=2.6%\]


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