A) 6
B) 7
C) 5
D) none of these
Correct Answer: B
Solution :
\[^{m}{{C}_{3}}+\,{{\,}^{m}}{{C}_{4}}>{{\,}^{m+1}}{{C}_{3}}\] |
\[\Rightarrow {{\,}^{m+1}}{{C}_{4}}>\,{{\,}^{m+1}}{{C}_{3}}\] |
\[\Rightarrow \,\,\frac{(m+1)!}{(m-3)!4!}>\frac{(m+1)!}{(m-2)!3!}\] |
\[\Rightarrow m-2>4\] |
\[\Rightarrow \,\,m>6\] |
\[\Rightarrow \]The least value of m is 7. |
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