A)
B)
C)
D)
Correct Answer: D
Solution :
Using Ampere's law, magnetic field of a solid conducting rod is \[B=\left\{ \begin{matrix} \frac{{{\mu }_{0}}I}{2\pi {{R}^{2}}}\cdot r & ,r\le R \\ \frac{{{\mu }_{0}}I}{2\pi r} & ,r>R \\ \end{matrix} \right.\] So, correct graph is [d].
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