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KVPY Sample Paper KVPY Stream-SX Model Paper-16

  • question_answer
    For the following reaction the mass of water produced from 445 \[{{C}_{57}}{{H}_{110}}{{O}_{6}}\] is \[2{{C}_{57}}{{H}_{110}}{{O}_{6}}(s)+163{{O}_{2}}(g)\to 114C{{O}_{2}}(g)+110{{H}_{2}}O(l)\]

    A) 490 g

    B) 445 g

    C) 495 g

    D) 890 g

    Correct Answer: C

    Solution :

    \[2{{C}_{2}}{{H}_{110}}{{O}_{6}}(s)+{{1630}_{2}}(g)\to 114C{{O}_{2}}(g)+110{{H}_{2}}P(l)\] \[\frac{Moles\,of\,{{C}_{57}}{{H}_{110}}{{O}_{6}}}{2}=\frac{Moles\,of\,{{H}_{2}}O}{110}\] \[\frac{\frac{445}{890}}{2}=\frac{\frac{Mass\,of\,{{H}_{2}}O}{18}}{110}\]  \[Mass\,of\,{{H}_{2}}O=495g.\]


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