A) \[BaC{{l}_{2}}\]
B) \[AlC{{l}_{3}}\]
C) \[NaCl\]
D) \[N{{a}_{3}}P{{O}_{4}}\]
Correct Answer: B
Solution :
A\[{{s}_{2}}{{S}_{3}}\]is a negatively charged sol. so \[AlC{{l}_{3}}\] will be most effective.
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