| Consider the following reversible chemical reactions: | |
| \[{{A}_{2}}(g)+{{B}_{2}}(g)2AB(g)\] | ...(1) |
| \[6AB(g)3{{A}_{2}}(g)+3{{B}_{2}}(g)\] | ...(2) |
| The relation between \[{{K}_{1}}\]and \[{{K}_{2}}\]is: | |
A) \[{{K}_{1}}{{K}_{2}}=\frac{1}{3}\]
B) \[{{K}_{2}}=K_{1}^{3}\]
C) \[{{K}_{2}}=K_{1}^{-3}\]
D) \[{{K}_{1}}{{K}_{2}}=3\]
Correct Answer: C
Solution :
| \[{{A}_{2}}(g)+{{B}_{2}}(g)2A(B)(g)\] | ? (1) |
| \[6AB(g)3{{A}_{2}}(g)+3{{B}_{2}}(g)\] | ? (2) |
| Reaction (2)\[=-\,3\times \]reaction (1) | |
| \[\therefore \] \[{{K}_{2}}={{\left( \frac{1}{{{K}_{1}}} \right)}^{3}}\] | |
| \[\Rightarrow \] \[{{K}_{2}}={{K}_{1}}^{-\,3}\] | |
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