A) \[10\mu V\]
B) \[70\mu V\]
C) \[90\mu V\]
D) \[100\mu V\]
Correct Answer: C
Solution :
Induced emf, \[E=\frac{d}{dt}{{\phi }_{B}}\] \[=a\int_{0}^{a}{\left( v\frac{\partial B}{\partial x}+\frac{\partial B}{\partial T} \right)}dx\] \[={{a}^{2}}\left( v\frac{\partial B}{\partial x}+\frac{\partial B}{\partial T} \right)\] \[={{(0.1)}^{2}}(0.08\times 0.1\times {{10}^{-\,3}})\] \[=9\times {{10}^{-\,5}}V\] \[=90\mu V\]You need to login to perform this action.
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