A) \[\frac{{{(x-5)}^{2}}}{25}+\frac{{{y}^{2}}}{16}=1\]
B) \[\frac{{{(x-5)}^{2}}}{16}+\frac{{{y}^{2}}}{25}=1\]
C) \[\frac{{{(x-5)}^{2}}}{25}+\frac{{{y}^{2}}}{9}=1\]
D) \[\frac{{{(x-5)}^{2}}}{9}+\frac{{{y}^{2}}}{25}=1\]
Correct Answer: A
Solution :
| \[4\tan \frac{B}{2}\tan \frac{C}{2}=1\] |
| \[\frac{s-a}{s}=\frac{1}{4}\] |
| Solve it \[b+c=10\] |
| Focus \[{{F}_{1}}\,\,(2,0)\] and \[{{F}_{2}}\,\,(8,0)\] and \[2a=10;\] |
| \[2ae=6;\] \[e=3/5;\] \[b=4\] |
| \[\frac{{{(x-5)}^{n}}}{25}+\frac{{{y}^{2}}}{16}=1\] |
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