KVPY Sample Paper KVPY Stream-SX Model Paper-17

  • question_answer
    Electrode potential for Zn electrode varies according to the equation.\[{{E}_{Z{{n}^{2+}}|Zn}}=E_{Z{{n}^{2+}}|Zn}^{^{{}^\circ }}-\frac{0.059}{2}\log \frac{1}{\left[ Z{{n}^{2+}} \right]}.\] The graph of \[{{E}_{Z{{n}^{2+}}|Zn}}\,vs\,\,\log \left[ Z{{n}^{2+}} \right]\]is

    A)

    B)

    C)

    D)

    Correct Answer: B

    Solution :

    \[{{E}_{Z{{n}^{2+}}|Zn}}=E{{{}^\circ }_{Z{{n}^{2+}}|Zn}}+\frac{0.059}{2}\log \,[Z{{n}^{+\,2}}]\] Comparing with \[y=mx+c,\] graph between \[{{E}_{Z{{n}^{2+}}|Zn}}\]and \[\log \,[Z{{n}^{2\,+}}]\] is a straight line with positive slope and positive intercept.


You need to login to perform this action.
You will be redirected in 3 sec spinner