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KVPY Sample Paper KVPY Stream-SX Model Paper-17

  • question_answer
    A force acts on a 2 kg object so that its position is Given as a function of time as \[x=3{{t}^{2}}+5.\] What is the this force in first 5 seconds?

    A) 850 J

    B) 950 J

    C) 875 J

    D) 900 J

    Correct Answer: D

    Solution :

    \[x=3{{t}^{2}}+5\]
    \[\Rightarrow \]   \[v=6t\]
    \[\Rightarrow \]   \[\Delta W=\Delta k\]
                \[=\frac{1}{2}(2)\,{{(30)}^{2}}-\frac{1}{2}2{{(0)}^{2}}\]
                = 900 J.


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