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KVPY Sample Paper KVPY Stream-SX Model Paper-17

  • question_answer
    A series AC circuit containing an inductor (20 mH), a capacitor\[(120\mu F)\] and a resistor \[(60\,\Omega )\]is driven by an AC source of 24 V/50 Hz. The energy dissipated in the circuit in 60 s is:

    A) \[5.65\times {{10}^{2}}\,\text{J}\]

    B) \[2.26\times {{10}^{3}}\text{J}\]

    C) \[5.17\times {{10}^{2}}\text{J}\]

    D) \[3.39\times {{10}^{3}}\text{J}\]

    Correct Answer: C

    Solution :

    \[E=pt=\frac{{{E}^{2}}}{{{Z}^{2}}}Rt\]
    \[=\frac{{{(24)}^{2}}}{{{60}^{2}}+{{(8.33\pi -2\pi )}^{2}}}(60)\,(60)\]
    = 518 J.


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