A) 640
B) 320
C) 321
D) 641
Correct Answer: D
Solution :
\[\Delta {{X}_{\max }}=d\sin \theta \]\[=0.32\sin 30=0.16\,mm\] |
\[\therefore \] \[n=\frac{\Delta {{X}_{\max }}}{\lambda }=\frac{0.16\times {{10}^{-3}}}{500\times {{10}^{-9}}}\]\[=\frac{0.16\times {{10}^{6}}}{500}=\frac{1600}{5}=320\] |
\[\therefore \] Number of BFs \[=\,(2n+1)=641.\] |
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