question_answer

The electrode potentials for \[C{{u}^{2\,+}}_{(aq)}+{{e}^{-}}\xrightarrow{{}}C{{u}^{+}}_{(aq)}\] and  \[C{{u}^{+}}_{(aq)}+{{e}^{-}}\xrightarrow{{}}C{{u}^{+}}_{(s)}\] are \[+\,0.15\,V\] and \[+\,0.50\,V\] respectively The value of \[E{{{}^\circ }_{C{{u}^{2\,+}}/Cu}}\]will be:

A) 0.500 V

B) 0.325 V

C) 0.650 V

D) 0.150 V

Correct Answer: B

Solution :

\[{{E}^{0}}=\frac{{{n}_{1}}E_{1}^{0}+{{n}_{2}}E_{2}^{0}}{n}=\frac{0.15\times 1+0.50\times 1}{2}=0.325\,V\]