A) \[1.6\times {{10}^{3}}\,km\]
B) \[3.2\times {{10}^{3}}km\]
C) \[6.4\times {{10}^{3}}km\]
D) \[1.28\times {{10}^{4}}km\]
Correct Answer: B
Solution :
\[{{E}_{1}}=-\frac{GMm}{R+h}-\left( -\frac{GMm}{R} \right)\] |
\[{{E}_{2}}=\frac{1}{2}m{{\left( \frac{\sqrt{GM}}{R+h} \right)}^{2}}\]\[=\frac{GMm}{2\,(R+h)}\] |
\[{{E}_{1}}={{E}_{2}};\] \[h=\frac{R}{2}.\] |
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