A) \[-\frac{d\,[A]}{dt}=k\,{{[A]}^{2}}\]
B) \[-\frac{d\,[A]}{dt}=k\,[A]\]
C) \[-\frac{d\,[A]}{dt}=\frac{k}{4}\,[A]\]
D) \[-\frac{d\,[A]}{dt}=k\,{{[A]}^{1/2}}\]
Correct Answer: D
Solution :
\[A\xrightarrow{{}}\,\,\text{Product}\] | |
We know, \[\text{Rate}=K\,\,{{[\text{conc}\text{. }\!\!]\!\!\text{ }}^{n}}\] | |
\[1\times {{10}^{-\,4}}=K\,\,{{[.01]}^{n}}\] | ..... (i) |
\[1.41\times {{10}^{-\,4}}=K\,\,{{[.02]}^{n}}\] | ..... (ii) |
(i) / (ii) \[\frac{1}{1.41}={{\left( \frac{1}{2} \right)}^{n}}\] |
\[n=\frac{1}{2}\] |
Then \[\frac{-\,d\,(A)}{dt}=K\,\,{{[A]}^{1/2}}\] |
You need to login to perform this action.
You will be redirected in
3 sec