A) \[9.1\times {{10}^{-31}}kg\]
B) \[1.6\times {{10}^{-27}}kg\]
C) \[1.6\times {{10}^{-19}}kg\]
D) \[2.0\times {{10}^{-24}}kg\]
Correct Answer: D
Solution :
\[eE=evB\] |
\[\Rightarrow \] \[E=\left( \frac{eBr}{m} \right)B\] |
\[\Rightarrow \] \[m=\frac{e{{B}^{2}}r}{E}\] |
\[\Rightarrow \] \[m=\,\frac{(1.6\times {{10}^{-19}}){{(0.5)}^{2}}\,(0.5\times {{10}^{-\,2}})}{100}\] |
\[=2\times {{10}^{-24}}kg.\] |
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