A) 0.77
B) 0.57
C) 0.37
D) 0.17
Correct Answer: C
Solution :
| \[f=\frac{1}{2\pi }\sqrt{\frac{C}{\left( \frac{M{{L}^{2}}}{3} \right)}}\] |
| And \[0.8f=\frac{1}{2\pi }\sqrt{\frac{C}{\left( \frac{M{{L}^{2}}}{3}+\frac{M{{L}^{2}}}{2} \right)}}\] |
| \[\Rightarrow \] \[\frac{25}{16}=\frac{\frac{M{{L}^{2}}}{3}+\frac{M{{L}^{2}}}{2}}{\frac{M{{L}^{2}}}{3}}\]\[\Rightarrow \] \[\frac{25}{16}+1+\frac{3m}{2M}\] |
| \[\Rightarrow \]\[\frac{9}{16}=\frac{3m}{2M}\]\[\Rightarrow \] \[\frac{m}{M}=\frac{3}{8}=0.37.\] |
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