A) \[\sqrt{2}a\omega \]
B) \[a\omega \]
C) \[\sqrt{3}a\omega \]
D) \[2a\omega \]
Correct Answer: A
Solution :
\[{{v}_{x}}=\frac{dx}{dt}=-a\omega \sin \omega t\] |
\[{{v}_{y}}=\frac{dy}{dt}=a\omega \cos \omega t\] |
\[{{v}_{z}}=\frac{dz}{dt}=a\omega \] |
\[\therefore \] \[v=\sqrt{v_{x}^{2}+v_{y}^{2}+v_{y}^{2}}=a\omega \sqrt{2.}\] |
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