A) \[{{x}^{2}}+{{y}^{2}}+4x-6y+19=0\]
B) \[{{x}^{2}}+{{y}^{2}}-4x-10y+19=0\]
C) \[{{x}^{2}}+{{y}^{2}}-2x+6y-29=0\]
D) \[{{x}^{2}}+{{y}^{2}}-6x-4y+19=0\]
Correct Answer: B
Solution :
Equation of circle |
\[{{x}^{2}}+{{y}^{2}}-6x-4y-11=0\] |
Since, OA and OB is perpendicular to PA and PB |
OP diameter of the circumcircle of\[\Delta PAB\]equation of circle is |
\[(x-3)(x-1)+(y-2)(y-8)=0\] |
\[\Rightarrow \]\[{{x}^{2}}-4x+3+{{y}^{2}}-10y+16=0\] |
\[\Rightarrow \]\[{{x}^{2}}+{{y}^{2}}-4x-10y+19=0\] |
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