A) 39
B) 40
C) 59
D) 60
Correct Answer: B
Solution :
Using Mosely's law for both cobalt and impurity |
\[\sqrt{f}=K\,(Z-1)\] \[\Rightarrow \] \[\sqrt{\frac{c}{\lambda }}=K\,(Z-1)\] |
\[\Rightarrow \]\[\sqrt{\frac{c}{{{\lambda }_{co}}}}=K\,({{Z}_{co}}-1)\] and \[\sqrt{\frac{c}{{{\lambda }_{x}}}}=K\,({{Z}_{x}}-1)\] |
\[\Rightarrow \] \[\sqrt{\frac{{{\lambda }_{co}}}{{{\lambda }_{x}}}}=\frac{{{Z}_{x}}-1}{{{Z}_{co}}-1}={{Z}_{x}}=40\] |
You need to login to perform this action.
You will be redirected in
3 sec