A) 1.18
B) 0.19
C) \[-\,0.19V\]
D) None
Correct Answer: C
Solution :
\[{{H}_{2}}S2{{H}^{+}}{{S}^{2-}}\] |
\[{{K}_{{{a}_{1}}}}.{{K}_{{{a}_{2}}}}=\frac{{{[{{H}^{+}}]}^{2}}[{{S}^{2-}}]}{[{{H}_{2}}S]}=\frac{{{({{10}^{-3}})}^{2}}[{{S}^{-2}}]}{0.1}\] |
\[\Rightarrow [{{S}^{2-}}]=\frac{{{10}^{-21}}\times 0.1}{{{({{10}^{-3}})}^{2}}}={{10}^{-16}}\] |
\[{{E}_{{{S}^{2-}}}}|A{{g}_{2}}S|Ag\]\[=E_{A{{g}^{+}}/Ag}^{{}^\circ }-\frac{0.0591}{2}\,\log \,\frac{[{{S}^{2-}}]}{[{{K}_{sp}}]}\] |
\[0.8-\frac{0.0591}{2}\log \frac{{{10}^{-\,16}}}{{{10}^{-\,49}}}=-\,0.19\,\,V\] |
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