A) \[p\]
B) \[p-1\]
C) \[2p+1\]
D) \[2p-1\]
Correct Answer: D
Solution :
\[f\left( x \right)\] is non-differentiable at only those points where \[P\]sin \[x\]acquires integral value. Now \[\sin x=\frac{r}{P}\]will have two solution in \[\left( 0,\pi \right)\]for and \[\sin x=1\]will have only one solution. \[\Rightarrow \]Total number of points of non-differentiability \[=\left( p-1 \right)+1=2p-1.\]You need to login to perform this action.
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