A) \[1.84\times {{10}^{-7}}\]
B) \[2.36\times {{10}^{-\,9}}\]
C) \[1.5\times {{10}^{-\,9}}\]
D) \[3.62\times {{10}^{-\,7}}\]
Correct Answer: C
Solution :
| Pyridinium hydrochloride is a salt of pyridine (weak base) and nydrochloric acid (strong acid). pH of a solution of strong acids and weak base can be calculated as |
| \[pH=7-\frac{1}{2}(p{{K}_{b}}+\log c)\] |
| \[\therefore \]\[3.44=7-\frac{p{{K}_{b}}}{2}-\frac{\log 0.02}{2}\] |
| \[p{{K}_{b}}=8.82\] |
| \[p{{K}_{b}}=8.82=-\log {{K}_{b}}\] |
| \[{{K}_{b}}=1.5\times {{10}^{-\,9}}\] |
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