A) Is more than 6
B) Is more than 3but less than 6
C) Is less than 12
D) Lies between 6 and 1
Correct Answer: C
Solution :
\[\left| {{z}_{1}}+{{z}_{2}}+{{z}_{3}} \right|=|\left( {{z}_{1}}-1 \right)+\left( {{z}_{2}}-2 \right)+\left( {{z}_{3}}-3 \right)+6\]\[\le \left| {{z}_{1}}-1 \right|+\left| {{z}_{2}}-2 \right|+\left| {{z}_{3}}-3 \right|+6<1+2+3+6=12\] \[ADCVICE\,:\text{try}\,\,\text{to}\,\,\text{find}\,\,\text{the}\,\,\text{geometrical}\,\,\text{interpretation}\,\text{by}\,\text{yourself}\text{.}\]
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