A) \[f\]
B) \[2f\]
C) \[f/2~\]
D) \[f/4\]
Correct Answer: A
Solution :
In the fundamental mode the air column in the open pipe (pipe open at both ends) vibrates with consecutive antinodes at its ends so that the length L of the pipe is equal to \[\lambda /2\] where \[\lambda \] is the wave length of sound in air. Therefore\[\lambda =2L.\] The air column in the closed pipe (pipe closed at one end) on the other hand vibrates in its fundamental mode, with a mode at the closed end (at the water surface inside the pipe) and the neighbouring antinode at the open end so that \[L/2=\lambda /4.\] Again we obtain\[\lambda =2L.\] The frequencies in the two cases are same.You need to login to perform this action.
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