A) 8
B) 2
C) 4
D) 6
Correct Answer: C
Solution :
Total number of stereoisomers = number of geometrical + number of optical isomers \[C{{H}_{3}}CH=CHC{{H}_{2}}CHBrC{{H}_{3}}\]is an alkene, so it can have two geometrical forms is and Irons. Since, the given compound has a chiral centre, therefore each geometrical isomer has a pair of enantiomer. Thus, in all there are \[2\times 2=4\] stereoisomers possible for given compound.You need to login to perform this action.
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