A) \[1.27\times {{10}^{23}}\]
B) \[3.63\times {{10}^{40}}\]
C) \[8.279\times {{10}^{45}}\]
D) \[0.03\times {{10}^{23}}\]
Correct Answer: C
Solution :
\[\Delta G{}^\circ =-262kJ=-262000J\] |
\[\Delta G=-2.303RT\log k\] |
\[\log k=\frac{\Delta G}{-\,2.30RT}\]\[=\frac{26200}{2.303\times 8.314\times 298}\] |
\[\log k=45.918\] |
\[k=8.279\times {{10}^{45}}\] |
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