A) 63.3 min
B) 53.3 min
C) 43.3 min
D) 30 min
Correct Answer: D
Solution :
For first order reaction \[t=\frac{2.303}{k}\log \frac{a}{a-x}\] |
For 90% reaction, \[100=\frac{2.303}{k}\log \frac{100}{100-90}\] |
\[k=\frac{2.303}{100}\log 10\] |
\[k=0.023\] |
Also, \[{{t}_{1/2}}=\frac{0.693}{k}=\frac{0.693}{0.023}=30.1\min \] |
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