A) 6
B) 4
C) 2
D) 0
Correct Answer: C
Solution :
We have, |
\[{{x}^{2}}-x\sin x-\cos x=0\] |
Let \[f(x)={{x}^{2}}-x\sin x-\cos x\] |
\[f'(x)=2x-x\cos x\] |
\[\underset{x\to \infty }{\mathop{\lim }}\,f(x)=\infty \] |
\[\underset{x\to -\,\infty }{\mathop{\lim }}\,f(x)=\infty \] |
\[f(0)=-1\] |
Hence, 2 solutions exists. |
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