A) 3.37
B) 5.26
C) 2.56
D) 4.62
Correct Answer: C
Solution :
\[0=(-\,0.151-0)-\frac{0.0591}{1}\log \,[{{H}^{+}}].\] |
\[0.0591\times \log \,[{{H}^{+}}]=-\,0.151\] |
\[pH=\frac{0.151}{0.0591}=2.56\] |
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